Collection

1999 Annual Conference

Authors

Cherian P. Mathews; Adrianne Candia; Waleed Kader

6HVVLRQ '63 , PSOHPHQWDWLRQ RI DQ $PSOLWXGH 0 RGXODWLRQ 7 U DQVPLVVLRQ 6\VWHP $ &DSVWRQH 'HVLJQ $SSU RDFK &KHU LDQ 3 0 DWKHZV $GU LDQQH &DQGLD :DOHHG .DGHU 8QLYHU VLW\ RI :HVW )ORU LGD *XOI 3 RZHU &RPSDQ\ 8QLYHU VLW\ RI )ORU LGD$ E VWUD F W$ OO V W X G H Q W V LQ W K H ( OH F W U LF D O ( Q J LQ H H U LQ J 3 U R J U D P D W W K H 8 Q LYH U V LW \ R I : H V W )OR U LG D 8 : )D U H U H TX LU H G W R X Q G H U W D NH D F D S V W R Q H G H V

Collection

1999 Annual Conference

Authors

Richard Martin

. Required Filter Characteristic.III. Intuitive Design - Use of logspace, freqs, abs, log10, and semilogxSince this seems like a simple enough filter to implement, let’s try a simple narrowband bandpassfilter having a second order denominator, with the form Vo Ka ω r s = . (1) Vi s 2 + ω r s + ω 2 r Q Page 4.571.2Noting that the + 5% variation in amplitude specified across the pass band is actually less than 1dB, let’s choose a bandwidth wider than 10 KHz, but less than 15 KHz, being aware of the needto reject frequencies just

Collection

1999 Annual Conference

Authors

John Parsons

the patient weighs 70 kg, has a heart rate of 70 beats/min. Then, for each minute, theheart pumps 70 beats/min * 70 ml/beat = 4900 ml/min. The mass would be 4.9 kg/min (mass density * volume). Wealso assume that cp (related to the heat capacity) for blood and the body is the same (0.87). Then one can do abalance (assuming that heat and temperature behave similarly),cp 1q -qn n +1 6 f 2 = - heart q n+1 - q chiller 7 [1] Dt mbodywhere:cp = exchange factor between the blood and bodyq n+1 = the body temperature at the next time step (degrees C)q n = the body temperature at the last time step (degrees C)f

Collection

1999 Annual Conference

Authors

Robert M. Ybarra

(1) DmWe did, however, created experiments to measure solid/liquid equilibria, q* and pore diffusioncoefficient, Dp followed by a capstone fixed bed adsorber experiment.Equilibrium Isotherm. The equilibrium isotherm describes how the adsorbate molecule distributesbetween an adsorbed state and bulk fluid phase. The familiar Langmuir isotherm model representsthe solid/liquid equilibria bc q* = 1 (2) 1 + b2 cIf the adsorption becomes highly favorable, the isotherm approximates a rectangular or irreversibleform (c = 0, q* = 0; c

Collection

1999 Annual Conference

Authors

Richard L. Coren; C. John Carpenter

unit length of this arrangement isC = qc/∆ϕ=qc/2ϕo (F/m), and the stored energy per meter is qc2/2C = qcϕo. Figure 1 showsthe lines immediately after we close the switch connecting the wires, showing the capacitordischarge as a result of current that flows along the lines.Since the velocity of electrical change propagates with the speed of light, c, the discharge surgemoves with this speed. It therefore removes capacitive charge at the rate I = qcc. Figure 1. Capacitive, moving charge relationsThe discharge results in a loss of capacitive potential energy. Ignoring radiation this must betransformed to kinetic because the current consists of conduction electrons, of density q +,moving at a mean drift velocity, u, so that I=q+u

Collection

1999 Annual Conference

Authors

John E. Nydahl; Nancy Peck

DQDO\VLV WR D V\VWHP¶V WKHRUHWLFDO PRGHO 7KLV LV DFFRPSOLVKHG WKURXJK WKH XVH RI WKHIXQFWLRQ FDSDELOLW\ WKDW PRGHUQ VSUHDGVKHHWV SRVVHVV ,Q WKLV FDVH D 9LVXDO %DVLF IXQFWLRQ PDFURLV ZULWWHQ WR FDOFXODWH WKH GHVLUHG H[SHULPHQWDO UHVXOW LQ WHUPV RI WKH PHDQ YDOXHV RI LWV PHDVXUHGSDUDPHWHUV 7KLV IXQFWLRQ LV WKHQ XVHG WR QXPHULFDOO\ HVWLPDWH WKH YDULDQFH RI WKH UHVXOW ZLWKUHVSHFW WR HDFK RI LWV PHDVXUHG SURSHUWLHV DQG WKHUHIRUH LWV UHVSHFWLYH VHQVLWLYLW\ WR HUURUV LQHDFK RI WKH PHDVXUHPHQWV DV ZHOO DV WKH H[SHULPHQW¶V PD[LPXP SUREDEOH HUURU 7KLV WHFKQLTXHSHUPLWV WKH LQYHVWLJDWLRQ RI PRUH FRPSOH[ DQG UHDOLVWLF V\VWHPV LQ D EHJLQQLQJ ODERUDWRU\ ,WDOVR SHUPLWV WKH XVH RI H[SHULPHQWDO GHVLJQ ERWK WR GHWHUPLQH ZKDW LQVWUXPHQWDWLRQ VKRXOG EHXVHG DQG KRZ

Collection

1999 Annual Conference

Authors

A. J. Baker; Z. Chambers; M. B. Taylor

4.268.10Page 4.268.11Page 4.268.12Page 4.268.13Page 4.268.14Page 4.268.15Page 4.268.16Page 4.268.17 FE.9 OPTIMAL WEAK STATEMENTMany choices exist for implementing WS q • does an optimal selection for Ψα (x) a n d Φα (x) discretized trial qh and test space basis sets exist? GWS WS

Collection

1999 Annual Conference

Authors

Oscar, Jr. Barton; Jacob Wallace

{ }xy ' [T]&1{ }12 { }12 ' [Q]{ }12 (2) { }12 ' [T]{ }xyIn eqn. (2), { F} is a 3 x 1 vector of stresses, { ,} is a 3 x 1 vector of strains, [T] is a 3 x 3 thecoordinate transformation matrix and [Q] is a 3 x 3 reduced stiffness matrix. The {12}subscript corresponds to the principal material direction, that which is parallel with the fibers ofa composite lamina and the {xy} subscripts corresponds to the non-principal materialdirection, the loading direction. For a given state of applied stress { F}xy, one is a able tocompute the principal material stresses, principal material strains and if needed, thecorresponding non

Collection

1999 Annual Conference

Authors

Digendra K. Das

. Initial Temperature = 60oF Final Temperature = 212oF Slope dT/dt = 1.52 Simulation time range = 0 - 100 sec. Page 4.348.2Model 2:A single, completely mixed chemical reactor with an inflow and an outflow was modeled. Thereactor is shown in Fig. 2.The mass balance equation for the reactor can be written as: V dC/dt = QCin - QC ----------- (2) where V = Volume Q = Flow rate C = Concentration Page

Collection

1999 Annual Conference

Authors

Arnoldo Muyshondt; Ing-Chang Jong

asanswer:the weight of a 1-kg mass;the weight of a 1-slug mass;the net forcerequired to accelerate a mass of 1 kg at 9.80665 m/s2;+the netforce required to accelerate a mass of 1 kg at 1 m/s2;the netforce required to accelerate a mass of 1 slug at 1 ft/s2tip:A 1-kg mass on the surface of the earth weighs about 9.81 N.;A 1-slugmass on the surface of the earth weighs about 32.2 lb.;It takes a net forceof 9.80665 N to accelerate a mass of 1 kg at 9.80665 m/s2.;Rightchoice!;It takes a net force of 32.2 lb to accelerate a mass of 1 slug at 1ft/s2.explanation:One newton is defined as the net force required to accelerate amass of 1 kg at 1 m/s2.points:10 4question:(10 points) Which of the following equations correctly relates thevectors F, P, and Q, as shown

Collection

1999 Annual Conference

Authors

Martin Bowe; Daniel Jensen

o d u c t • C r e a t e m o r p h o lo g ic a l m a t r ix • Id e n ti fy fu n c tio n s h a r in g a n d c o m p a tib ility • T r a n s fo r m to e n g in e e r in g s p e c s . & m e tr ic s ( Q F D ) 6. Design Models • Id e n ti fy a c tu a l p h y s ic a l p r in c ip le s • C r e a t e b a l a n c e r e la tio n s h ip s • C r e a t e e n g i n e e r in g m o d e ls a n d m e tr ic r a n g e s — E x a m p le m o d e ls : c o s t, h e a t tr a n s fe r , s tr e s s , s tr e n g th , life - c y c le ( D F E ) , a s s e m b

Collection

1999 Annual Conference

Authors

Timothy Robert Wyatt; Emir Jose Macari

permit more insight into the eventual testresults. For example, on the Yield Surfaces screen, the MCC yield surface, corresponding to theuser-provided values of Μ, e, and p′0, was plotted in a two-dimensional q-p′ space, and wouldchange size/shape instantaneously as the user edited the input. The user was not required toaccess these investigation screens in order to perform a test simulation. It was believed thatstudents would be naturally curious to learn more about the impact of their data input on theoverall test results, and would be independently motivated to access the investigation screens.By clicking the Help buttons, the user could view the underlying equations for eachinvestigation screen. The program structure including investigation

Collection

1999 Annual Conference

Authors

Sam Thompson; John I. Hochstein; Tom Benson; Jeff Marchetta

University, The Netherlands; .10. Torella, C. and Lombardo, C., “Computer Codes for the Training on Auxiliary Power Units (A.P.U)”, AIAA Paper 94-3113.Appendix AQ I: For Mach number = 2.5 and wedge angle = 10o, what is the shock angle?Q 2: What is the Mach number downstream of a 20.0 degree wedge at Mach 3.5?Q 3: For Mach number = 2.0 and wedge angle = 24.0o, what is the shock angle? What type of shock is this?Q 4: For Mach number = 2.0 and wedge angle = 24.0o, is the downstream flow supersonic or subsonic? Why?Q 5: For Mach number 3.0, how does the static pressure ratio vary with wedge angle? At what wedge angle does the shock become a normal detached shock? How does the static pressure ratio vary with wedge angle after the shock becomes

Collection

1999 Annual Conference

Authors

Milin Shah; Guoqing Tang; Bala Ram

components andthe total cost are: PC (q) = p , where p is a constant, OC (q) = kr , where k is per order qcost, r is demand of units per year, both being constant, and q is the order quantity, HC (q) = hq , where h is the carrying cost and is a constant, and 2TC (q ) = PC (q) + OC (q ) + HC (q) = p + kr + hq . q 2 Figure 1: Cost Components of the Car Replacement Problem Figure 2: Cost Components of the Inventory Control ProblemThe total cost may be annualized (expressed as an annual cost) and expressed as afunction of either the retention period for the car replacement problem, or the

Collection

1999 Annual Conference

Authors

Sol Neeman

-. It will provide the amplitudesof the frequencycomponentsof the signal, the fundamental ,_ frequencyand.ite harmonica.In the case of non-periodicsignals, we can ap_‘ .~ : .-&&cit&j jjlourier_.Integral. j&Q& it&* so-&n && &e fFequnncy :. ~:~e&3 con@&gthesignal,.thistransformdoesnotprovideinf~ c tion on the tim&equency relationsin the s@aL The Fhrier ‘Ikansform does not provideinformationthat would let us associatecertainevents (e.g. abrupt changes,long term behaviorof a s&al) with certain points of time. , TlG3 presentationc811providea

Collection

1999 Annual Conference

Authors

John, Jr. Lipscomb

60 Percent 60 50 40 40 20 30 20 0 A C E G I K M O Q A C E G I K M O Q Program ProgramAnother approach to diversity was comparing the hours taught by each program with the Globalhours taught shown in the graph above and right. This graph has more resolution than the priorgraph because it not only counts the topic but includes the hourly emphasis on the topic by eachprogram. An

Collection

1999 Annual Conference

Authors

Robert Borchert; David Yates; Daniel Jensen

Values for Each Lecture for S-type, N-type, K-type and V-typeStudents for Each of the 4 OMS Questions Page 4.186.12Students rated each of the lectures on a 1-10 scale for each of the 4 questions on the OMS. Thelecture ratings from students having MBTI S-type were separated from those students who wereN-type, while those who had VARK K-type were separated from those who had V-type. The S-type, N-type, K-type and V-type students’ rating were averaged for each lecture. In the Q Q Qcalculations below, these averaged lecture ratings are denoted X , X X and

Collection

1999 Annual Conference

Authors

Michael Sexton

shaft speedYou are to determine the engine operating parameters as the engine fuel rate is decreased in10% increments back to 50% fuel flow (i.e., operating parameters for 90, 80, 70, 60, and 50% Page 4.272.2fuel flows). Compressor and turbine characteristics are as provided in Figs. 2 and 3. Providesummary of operating parameters, computer program, sample calculation, and discussion ofresults. q To3=2000 R Work out = 500 hp ηc=84% ηt=90

Collection

1999 Annual Conference

Authors

M. Mavromihales; K. Sherwin

based on the MTD approach. The basis equation for any heat exchanger is: Q = UAdTm (1)where dTm is the mean temperature difference.Where the temperature changes within the water and air are much smaller than the overalldifference in temperature between the fluids, it is sufficiently accurate to take an arithmeticmean temperature difference: dTm = ((Tw1 + Tw2) - (Ta1 + Ta2))/2 (2)Using these equations the design can be based on an initial simple heat transfer model, inorder to allow the students to rapidly get to grips with the problem, which can then be refinedto make it more realistic.First modelThe initial

Collection

1999 Annual Conference

Authors

Robert A. Johnson; J. Shawn Addington

forusing the outcome indicators, the assessment plan will evaluate each individual outcome in asimilar manner to observe, analyze and evaluate the achievement of the program’s intendededucational outcomes, utilizing input from the program's constituents and feedback of the resultsto those constituents. Page 4.308.11 A LL EE CO URSES A V E R A G E Q U A N T IT Y O F O P P O R T U N IT Y 54 .5 43 .5 32 .5 21 .5 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 E D U C A T IO N A L O U T C O M

Collection

1999 Annual Conference

Authors

Ronald James; Janet L. Gooder; Charles Wisniewski; Brenda Haven; A. George Havener

Energy Stored in the System system out + Wout + m & θout & & in + Win + m &θ & Q & Q in dE  dU d ( KE ) d ( PE ) d (U o

Collection

1999 Annual Conference

Authors

Robert Vance; Gloria Elliott; Craig W. Somerton

pts) Page 4.309.3students are given some direction as to the measurement of transmissivity. Basically, they aretold to consider the physical situation shown below qrad,in qrad,outwhere the transmissivity is defined as q rad,out τ = q rad,inThen to measure the transmissivity the students must consider the following: 1. A way to produce a radiation heat flux 2. A way to measure the radiation heat flux 3. A way to separately determine qrad,in and qrad,outThe lecture concludes by demonstrating the equipment that is available

Collection

1999 Annual Conference

Authors

John D. Cremin

A IR B O R N E /M A R IN E D G P S R E C E IV E R S DGPS GROUND SY STEMFigure 1 Block Diagram of GPS and DGPS Configuration Page 4.274.3 E Q U IP M E N T U S IN G N A V D A T A N M E A O R A R IN C RF FORM AT RF FROM R E C E IV E R P O S IT IO N RTCM FRO M G PS FRONT C A L C U L A T IO N FO RM

Collection

1999 Annual Conference

Authors

Shani Francis; Neal Pellis; Keith Schimmel

, solution implementation, and solutionevaluation. Topics covered in the module will include ones that are typically covered inintroductory numerical methods and data analysis courses. Initial testing of the module is in asophomore level introduction to chemical engineering analysis and design course.I. IntroductionTeaching is most effective and most fun when the student is properly motivated. A significantproblem in engineering education today can be motivation of students. Given that oftentimes astudents M-Q (motivation quotient) is more important to success than their I-Q (intelligenceqoutient) (Hendricks, 1987), the importance of finding ways to properly motivate students cannotbe underestimated. The goal of the multimedia module under

Collection

1999 Annual Conference

Authors

Laura J. Genik; Craig W. Somerton

the design team will solve Page 4.544.11the 2-D energy equation for this configuration. It is suggested that the design team implementthe numerical method on a spreadsheet or in a computer program. The minimum number ofnodes is 9. The dimensions of the rectangular fin are 0.45 m by 0.08 m. It is recommend that adirect matrix inversion method be used. The memo should include the nodal equations as wellas the matrix formulation.  ∂ 2T ∂ 2 T  0= k 2 + + q& ′′′ ∂ x ∂ y 2

Collection

1999 Annual Conference

Authors

Timothy Robert Wyatt; Pedro Arduino; Emir Jose Macari

is reached). For a drained test, with cell pressure = 50 kPa and preconsolidation pressure = 100 kPa, this occurs at q = 50 kPa. The axial strain at this ultimate state is about 0.5. You should have noticed a dramatic increase in strain at about q = 35 kPa when the material yielded. After this point the soil experienced plastic deformation. You can verify this by unloading the specimen (the minus key). There is very little elastic rebound. Go back to the Test Conditions dialog box. Click on the q-vs.-p plot type, then click OK. You now should see two plots, one with a linear stress path and the other with a very non-linear stress-strain curve. Reset the specimen by clicking the Home key. Go back to the Test Conditions

Collection

1999 Annual Conference

Authors

Sheila Palmer

studentsderive the equations in groups. I gave them a leading handout and they were to fill in the blanks.The text of the handout follows. T ds EQUATIONS: ALL equations that you write should be on a differential basis (e.g., the heat transfer is expressed as q and e is written as de.) 1 - Write the Conservation of Energy equation for a closed system. 2 - Divide the above equation by the system mass. 3 - If changes in kinetic and potential energy are negligible, what is the simplified expression for de? 4 - If the process is internally reversible, write the expression for the heat transfer as given by the definition of entropy. 5 - If the only work involved is boundary work, what is the expression

Collection

1999 Annual Conference

Authors

Tom Ward; Elizabeth Alford

: cause and effect, analogy, generalization,classification, authority, and motive. Other option elements of the model include Backing (B), if necessaryto support the Warrant; a Rebuttal (R), which recognizes the conditions under which a Claim will not betrue or justified; and a Qualifier (Q), which expresses the degree of certainty of the Claim.10 Therefore Data (D) Claim (C) Qualifier (Q) “probably”Engineer Adams surveyed building Adams should 1) send second

Collection

1999 Annual Conference

Authors

George Stephanopoulos; Alan S. Foss

with which the physicsand phenomena of the process are identified and engineering science concepts placed into a modelstructure simply by declaration. Such declarations are made through use of our new software thatassembles the phenomena declared, builds the equations, and solves the equations numerically. Thesoftware is novel and unique; ModelLA is its name. With a functioning model, students can examineits characteristics and use such quantitative information to solve the engineering problem posed. Following such an encounter with the cause and effect among variables, students are muchbetter prepared than they were at the outset to write equations for the model. Through Q and A in aworkshop session, the instructor leads the students

Collection

1999 Annual Conference

Authors

Todd Jammer; Laura J. Genik; Diana Beavers; Craig W. Somerton

coordinate conditions are at y =0 a prescribed heat flux and at y = b a specified temperature condition. The boundary conditionmodifier (B21) on the y-coordinate at y = 0 the prescribed heat flux is a function of time q(t) =ct and the boundary condition at y = a is a non-zero specified temperature. Once a problem iscategorized, one may then select the appropriate Green’s Function solution. There also exists asupplement to Beck’s book that categorizes the solutions in Carslaw and Jeager [3] with thesame system. A Green’s Function may be determined for these problems as well.This paper continues with a description of the Nusselt number correlation classification system.Then two tools to utilize the system are presented, a PC DOS program and a web