AC 2010-1674: THE DEVELOPMENT OF A Q-MATRIX FOR THE CONCEPTASSESSMENT TOOL FOR STATICSAidsa Santiago Roman, University of Puerto Rico, Mayagüez Aidsa I. Santiago Román is an Assistant Professor in the Department of Engineering Science and Materials and the Director of the Strategic Engineering Education Development (SEED) Office at the University of Puerto Rico, Mayaguez Campus (UPRM). Dr. Santiago earned a BA (1996) and MS (2000) in Industrial Engineering from UPRM, and Ph.D. (2009) in Engineering Education from Purdue University. Her primary research interest is investigating students’ understanding of difficult concepts in engineering science with underrepresented populations. She also
angular velocity and rotation about a fixedaxis, the military tank shows even more value illustrating rotating reference frames and theconcepts of relative motion. For planar motion, the military tank can be thought of as twodistinct reference frames – the chassis reference frame and the turret/barrel reference frame.Students can relate to these two distinct reference frames because they already know theindependent motion of the turret with respect to the chassis. If the chassis (reference frame N)remains fixed to the ground and does not rotate but the turret (reference frame T) is free to rotate,the relative motion of two points, P and Q on the turret can be discussed (Figure 4). By fixingthe chassis of the tank to the ground, we can establish a
std_logic); method Bool lampGreenM();attribute LOC: string; method Bool lampRedS();attribute LOC of clk0: signal method Bool lampAmberS();is "P11"; method Bool lampGreenS();attribute LOC of State: signal is endinterface: TL"P02,P03,P04,P06,P07,P08";end entity ; typedef enum {architecture Behavior of trafficlight is GreenM, AmberM, RedM,signal Q: std_logic_vector (1 downto 0); GreenS, AmberS, RedS} TLstatesbegin deriving (Eq, Bits);process (clk0,Q) (* synthesize *)begin
] matrixis typically denoted as the [Q] stiffness matrix for loading that coincides with the fiber direction ] _(i.e., 0° angle) and is denoted as Q for loading at a non-zero angle with respect to the fiberdirection.The first example modeled by the students in this course is for an isotropic material in loaded inplane stress at a 0° angle where the material properties are given as E11 := 207·GPa, E22 :=207·GPa, ν12 := 0.33 and G12 :? E11 ? 77.82 GPa . Using these material property 2 * ∗1 − π 12 +values, the students determine the values of the [Q] matrix elements: 232.297 76.658 0
.Bar Structure Stochastic Static Analysis8Before doing any computer solutions, let us discuss a simple one element baranalysis without making any reference to any computer programs or results.Figure 4 shows a cantilever bar of length L, cross sectional area A, the materialmodulus of elasticity E, and the bar is subject random axial load Q. In addition,let us assume that one of the parameters of A, L E and Q is random at a time. Page 15.922.8 7 EA Q L qFigure 4: Cantilever Bar
theexpression for predicting the range of acceptable sample frequencies for such a bandpass signal is Q Q−1 2B ≤ Fs ≤ 2B (1) n n−1 Page 15.1328.1where Q = fU /B, and n is an integer such that 1 ≤ n ≤ ⌊Q⌋. In most real-world examples, thesignal’s frequency content is already specified, leaving n as the first choice the students must learn to Valid sampling frequencies for BP sampling
. Page 15.305.2 Figure 1: Illustration of Public-key Encryption and Decryption4Students have always been curious to this feature. At this point, we use an instructional example,as listed in Table 1, to involve students into a public-key cryptosystem including key generation,encryption and decryption. Table 1: Public-key Algorithm Step Description Example Step 1 Randomly select two prime numbers, denoted by P and Q i.e., P=11, Q=17 Step 2 Compute the modulus M=P*Q, M is made publicly available M=11*17=187 Step 3 Compute the Euler totient as T= (P-1)* (Q-1) T=(11-1)*(17-1)=160 Step 4
. Collect team answer sheet 7. Provide correct responses 8. Students self grading- compare individual average scores and team based average scores 9. Team reflection and reworking the incorrect responses 10. Collect all remaining materials and end the sessionAnalysisIn this section, we present a description and analysis of selected episodes from the recordedobservational data of the two teams working on the rocket configuration quest. These episodeswere selected as they relate to our research goals to determine the major events teamstransitioned through to select a shared team answer. Our unit of analysis is at the team level.Team A spent a bulk of their time in negotiating a response to Q.1., and team B had extensiveinteraction negotiating
are separated; space (B) contains the resulting mixture when bothcomponents are mixed. Both spaces are insulated (Q=0) in this closed system with no work term (W=0), so that onecan conclude from the first law (Q+W= ∆U ) that: ∆U = 0 U A = U B ;U ≡ internal energy (3) 4Although the energy levels are the same, one notes that system (A) has the capability of doing useful work (because ofthe high-temperature high-pressure steam) while system (B) does not. If an entropy analysis is performed (seeIllustrative
are separated; space (B) contains the resulting mixture when bothcomponents are mixed. Both spaces are insulated (Q=0) in this closed system with no work term (W=0), so that onecan conclude from the first law (Q+W= ∆U ) that: ∆U = 0 U A = U B ;U ≡ internal energy (3) 4Although the energy levels are the same, one notes that system (A) has the capability of doing useful work (because ofthe high-temperature high-pressure steam) while system (B) does not. If an entropy analysis is performed (seeIllustrative
modifications have been made on a regular basis.Table 4. Mentor evaluation of students in a team6 Draft Average grade Q. 2. Q. 3. Q. 4. Q. 6. score from Q. 1. Work Do Informed Q. 5. Listened out of 5 mentorStudent Meeting before team team if Contributed to team from (NG toname attendance meetings tasks absent in meetings mates Q 1-6 A+) AverageFigure 2 shows the 2008/2009 winners of the prize for the top team in the module along
changes each time the student accesses the exercise, so this exercise is only partiallystatic.The process of checking the student results in this case uses a conversational style, simulating whatan instructor might do when discussing student results in person. At the end, if all six parts arecorrect, the student is given positive feedback: Fall 2010 Mid-Atlantic ASEE Conference, October 15-16, 2010, Villanova University Figure 4: Two–user RSA Key ExampleUserID: frede is correct, let’s check p next:bitLength(p) == 128, good...p is prime, almost there for p...gcd(e,p-1) == 1, p is ok, let’s check q next:q != p, that’s a good start...bitLength(q) == 128, good...q is prime, almost there for q...gcd(e,q-1) == 1, q is ok, let’s
being negligible the 1st law of thermodynamics Page 15.1073.12during the heating process is: dE dU du & & = =m = Q −W dt dt dtc). Heat is transferred in via the radiant solar energy collected. Using the data collected,find an average value for Q& in during the heating process: Heat is transferred from the pot due to free convection which depends on thetemperature difference between the water and the surroundings. A theoretical estimate ofthis transfer can be determined to be
undergraduate students. (j) I found the book to be very useful for biomedical engineering technology. It was not so theory orientiented which I think make the book more applicable at this level.Appendix B MEDICAL IMAGING EQUIPMENT E-BOOK STUDENT SURVEY AT EAST TENNESSEE STATE UNIVERSITY In August you were given an e-book “Medical Imaging Equipment Theory” for educational purposes in your course Medical Imaging Equipment, ENTC 4390. In order to help develop this text material and assess its effectiveness please fill in the following survey and return it to your teacher. The individual students are identified by letters of the alphabet A to Q (Spelling and grammatical errors are not corrected in the responses, as
the heat exchanger. Location 4 is the cold water leaving the heat exchanger. Page 15.57.4The water in the tank is at temperature T1. The hot water enters the heat exchanger at thistemperature.From the first law of thermodynamics, the rate of heat removed from the hot water, Q, isequal to the rate of decrease of the internal energy of the hot water. d T1 Q ? / τ cV (1 ) dtwhere: Q = the rate of heat transfer ρ = density of the water in the tank c = specific heat of the water in the tank V = volume of water in the tank
ux uy uz 0 (19) t x y z x y y zHeat transfer in the flowing fluids occurs by both convection and conduction. The energybalance for the flowing fluids in the pipes is: T T T T 2T 2T 2T C p C p u x uy uz k x 2 k y 2 k z 2 Q (20) t x y z x y z After obtaining the components of the velocity vector by solving the Navier-Stokes equations,the energy balance equation can be solved and the temperature profiles can be determined.iii. Boundary ConditionsFor the Navier-Stokes equations, the
allowable values. If the user wants apictorial representation of the variable, he or she may click on the variable and a pop-upbox will provide this information.Just to the right of the INPUT values are the OUTPUT variables. The OUTPUTvariables, chosen specifically for this problem are: the gas temperature T, the cylinderpressure P, the volume & change in volume Vol & ΦVol, the initial, instantaneous, andchange in internal energy U1, U, & ΦU, the heat transfer Q, and the work W. As with theINPUT variables, the variable definition and units are displayed when the user hovers themouse over the given variable.If the user would like to add or delete OUTPUT variables, he or she can click on theOUTPUT button and a pop-up screen appears
(six per category): standard problems and inferential problems. The problems in both the categories were small and simple; they did not require complicated mathematical formulas or calculator to solve them. a. Standard problems: The standard or textbook type problems were similar to the ones covered during the course in class assignments, home assignments and exams, with minor variations in numerical values and problem setup. Students were given sufficient practice on like problems. Two typical standard problems are given below: Q#25 Find ‘Vout’, as indicated, for the following circuit: Note: A typical voltage-divider-network; students had sufficient
. . . . . Q m = Q con + Q cov + Q rad + Q evp . Q m = 0.0533(m)( p ) + 1.64 = 1.802WResults:Modeling the system as a second order approximation, the time it takes for the temperature toreach steady state, and the percent overshoot can be calculated. Shown below in Figure 2 is amodel of the second order system. Figure 2 ~ Second Order Approximation of Incubator Temperature Control Figure 2 ~ Temperature Control Model OutputThe overshoot of temperature will be adjusted to be as close to 0% as possible. This will be donewith the design of a controller.The heat loss per unit area of the housing of the incubator system was calculated to be 1.56 .The total surface
∀ ∀0 2u > x > ♣and represents a concentrated load of magnitude one 2 at x ? 0 . Macauley represented the Diracdelta function at x ? a as a bracket with a subscript of –1. x / a /1 ? φ ∗x / a+ ? 0 x ≈ a (2) Page 15.549.3The unit doublet, or concentrated couple or moment can be represented graphically as follows: q(x,u) 1 u2 0 u 2u x 1 / u2 Figure 2: Graphical display2 of the unit doublet function at x=0.The unit doublet function at x ? 0 is defined as: ∀0 / ♣ ∞ x ∞ 0
52 32% VQQ 63 38% VQV 1 1% VQVQ 7 4% Q 7 4% QQ 11 7% QQV 2 1% Did not view media or complete assessment 5 3% TOTAL 164 100% Q: Attempt at online assessment/quiz
learning, all examples will be first solved by the traditional method ofintegration (MoI) with the use of singularity functions then solved again by the method ofmodel formulas (MoMF). As usual, the loading function, shear force, bending moment, slope,and deflection of the beam are denoted by the symbols q, V, M, y , and y, respectively.Example 1. A cantilever beam AB with constant flexural rigidity EI and length L is acted on bya concentrated force of magnitude P at C, and two concentrated moments of magnitudes PL and2PL at A and D, respectively, as shown in Fig. 2. Determine the slope A and deflection yA atend A. Fig. 2. Cantilever beam carrying a force and two momentsSolution by MoI. Using the symbols defined earlier
engineering school Why are the U.S. News Graduate Engineering Rankings Helpful to Consumers?q What does all of this mean in today’s global information marketplace?q U.S. News--over the last 25-years--has become a trusted, respected and unbiased source of engineering rankings and assessments that prospective engineering school students in the U.S. and worldwide turn to for reliable advice and guidance. Graduate Engineering Schools Ranking Factors: Inputs and Outputs w A combination of inputs and outputs are used in the Graduate Engineering ranking model that are a mixture of statistical and opinion data. w Inputs include: n Research activity n Faculty resources n Student selectivity w Outputs include
receiver forsymmetrical signals with perfect carrier and bit time synchronization (Figure 3). The theoreticalprobability of bit error (Pb) for a symmetrical BPSK signal in AWGN and with optimalreception, assuming that the apriori probabilities of the binary data and the energy per bit areequal (P0 = P1 = 0.5 and Eb0 = Eb1 = Eb), is presented in the course lecture5. 2 Eb Pb Q NoThe function Q is the complementary error function and No is the power spectral density of theAWGN. The optimal threshold for the correlation receiver is set as τopt = 0. MATLAB/Simulinkcan calculate the statistics of the binary data
CoworkersAs with managers, new engineers at every company reported varying degrees of help from thecoworkers. Many participants said that their coworkers helped them understand what is expectedof them and helped them accomplish their work. Other participants said that their coworkerswere too busy or too new to the work group to provide much help. Q: Did your [coworker] give you this assignment? A: Yes. Q: I assume he gave you background information? A: Yes and no. We both were new to this [name] system, so we pretty much were on the same page in terms of understanding the system. So it was like we both learned it at the same time. I found some information, I talked to him about it, he found some more information
(MoMF). As usual, the loading function, shear force, bending moment, slope,and deflection of the beam are denoted by the symbols q, V, M, y , and y, respectively.Example 1. A simply supported beam AD with constant flexural rigidity EI and length L is actedon by a concentrated force P at B and a concentrated moment PL at C as shown in Fig. 2.Determine (a) the slopes A and D at A and D, respectively; (b) the deflection yB at B. Fig. 2. Simply supported beam AD carrying concentrated loadsSolution. The beam is in static equilibrium. Its free-body diagram is shown in Fig. 3. Fig. 3. Free-body diagram of the simply supported beam AD● Using MoI: Using the symbols defined earlier and applying the method of
1.328Wing Re wing Do,wing C Do,wing q Swet ,wing Re wing VtrimL C Do , fusela ge 1.328Fuselage Re fusela ge Do, fusela ge C Do, fusela geq Swet , fusela ge Re fusela geHorizontal VtrimcHT 1.328 Re HT C Do , HT Do, HT C Do, HT q Swet , HTTail
Page 15.356.11KK=A+A'-diag(diag(A))KK=KK.*area% apply boundary conditions for temperature T1=100 and T7=680K=KK;K(1,1)=1; K(1,2)=0;K(el_no+1,el_no)=0;K(el_no+1,el_no+1)=1;%apply nodal heat loadsheatload=zeros(el_no+1,1);heatload(1,1)=230; heatload(el_no+1,1)=50;%Solve for unknown nodal temperatures (t)t=inv(K)*heatload%find nodal heatq=zeros(el_no,1);for i = 1:el_no q(i)=area.*U(i).*(t(i+1)-t(i));end%q Page 15.356.12
Multidisciplinary Project:RF CMOS Voltage Controlled Oscillator (VCO) that is capable of generating an outputfrequency near 5GHz for monitoring neural and cardiac activities. The circuit topologyhas been chosen to achieve such high frequency with high Q-factor. The team project Page 15.974.6works on the transmitter circuit and its layout with L-Edit software is given. Thisincludes the prescribed inductances and capacitances required to achieve the designspecifications. Figures 4 and 5 show the schematics of an rf amplifier that was simulatedwith PSpice, and the result is given in figure 6. The results provide the 5 GHz VCO thatmeets the design specifications. The
range of -10 to 110 °C. Asmall brushless DC fan is attached to the base to provide optional cooling (not demonstratedhere). The control input to the heater is supplied from the PWM output of the micro controllerthrough the H-Bridge amplifier on the Interface Board. The temperature is measured using the10-bit A/D converter on the micro controller. With a voltage reference of 2.5 volts for the A/D,the temperature measurement resolution is 0.244 °C. The heat output rate q from the heater isdirectly proportional to the heater voltage v: q = Kv, where K = 10/12 W/V. Page 15.1157.5 Fig. 3 Plate and heater experimental