. Page 5.335.3Figure. 1 – Average Scores on Survey – In order of Importance y y à v h t r t t r v y p v y q v y v p h r v r p p h y à h h y à q y r r h r
{ }xy ' [T]&1{ }12 { }12 ' [Q]{ }12 (2) { }12 ' [T]{ }xyIn eqn. (2), { F} is a 3 x 1 vector of stresses, { ,} is a 3 x 1 vector of strains, [T] is a 3 x 3 thecoordinate transformation matrix and [Q] is a 3 x 3 reduced stiffness matrix. The {12}subscript corresponds to the principal material direction, that which is parallel with the fibers ofa composite lamina and the {xy} subscripts corresponds to the non-principal materialdirection, the loading direction. For a given state of applied stress { F}xy, one is a able tocompute the principal material stresses, principal material strains and if needed, thecorresponding non
pixels for CCS pixels q.k =digital value of band k of pixel q In the base image, for each pixel in the CCS area, we will ED + = ( p.k − q.k ) 2search for its most similar pixel. In another word, we need to if ED ≠ 0 // Makes sure p and qlook for a pixel with the most similar surface reflectance // are not identicalvalues in the spectral space. This is called closest spectral fit if j == 1(CSF) [1]. Since the pixels in CCS area have been spectrally
instructor's knowledge of the subjectQ1_12 course is informative and usefulQ1_13 course is interestingQ1_14 class experienceTable 2. Matched categories of factors for Q1. Responses to Question1 10 9 8 7 responses 6 5 4 3 2 1 0 Q 0 Q 1 Q 2 Q 3
resistive lattice. For example, for an infinite 2D Honeycombresistive lattice (see Fig. 2) where M = 3, the effective resistance between any two adjacent nodesis simply Reff = 2R/3, where R is the value of each resistor on each branch of the lattice.Similarly, M = 6 for an infinite 3D cubic resistive lattice and, therefore, Reff = 2R/6 = R/3. Page 14.300.5 Ia = I (or Qa = Q) a + Va-b Infinite R, L, (or νa-b
. 2) Draw the normal probability plots to show whether the grades are from the normal distribution. If the sample is normal, the plot will be approximately linear. Other distribution types will introduce strong nonlinearity in the plots. 3) Draw the quantile-quantile (Q-Q) plot to show whether the two grade samples come from the same unknown distribution. If the two samples do come from the same unknown distribution, the plot will be linear. 4) Use the Shapiro-Wilk test to see if the two grade samples are both from the normal distribution family. If both samples are from the normal distribution family, the F-test and the t-test are further used to see if the
] matrixis typically denoted as the [Q] stiffness matrix for loading that coincides with the fiber direction ] _(i.e., 0° angle) and is denoted as Q for loading at a non-zero angle with respect to the fiberdirection.The first example modeled by the students in this course is for an isotropic material in loaded inplane stress at a 0° angle where the material properties are given as E11 := 207·GPa, E22 :=207·GPa, ν12 := 0.33 and G12 :? E11 ? 77.82 GPa . Using these material property 2 * ∗1 − π 12 +values, the students determine the values of the [Q] matrix elements: 232.297 76.658 0
several different models to study, just one will bedemonstrated here. This example will consist of a rear wheel driven car which has a cordor ribbon directly wrapped around the rear axle and pulled by the arm connected to thespring. The simplified drawing of this model of this is shown in figure 1. D q d L rear front B Page 7.870.2 Figure 1 “Proceedings of the 2002 American Society for Engineering Education Annual
) . n i =1 1 Λ 1 To generalize the results in section 2, a few preliminaries are necessary. Let N n = Μ Ο Μ be 1 Λ 1the n-by-n matrix whose entries are all 1's. For instance N 1 2 is a 12-by-12 matrix. One says thatan n-by-n matrix, Q, is doubly stochastic if the entries of Q are nonnegative, and the sum of theentries in each row and column is 1. In the previous section, the neighborhood
.Bar Structure Stochastic Static Analysis8Before doing any computer solutions, let us discuss a simple one element baranalysis without making any reference to any computer programs or results.Figure 4 shows a cantilever bar of length L, cross sectional area A, the materialmodulus of elasticity E, and the bar is subject random axial load Q. In addition,let us assume that one of the parameters of A, L E and Q is random at a time. Page 15.922.8 7 EA Q L qFigure 4: Cantilever Bar
were designed to assess student learning andthe effectiveness of the new course design. In order to evaluate the student background inLLL (step 1), a survey was administered at the beginning of the semester. A copy of thesurvey is presented in Table 1. Page 23.223.4Table 1. Survey questions used to evaluate the student background and understanding of Life-long learning. Q-1 From the following four options, select the one that describe your personal knowledge of the concept of “Life-long learning”? A. Extensive B. Moderate C. Limited D.No idea Q-2
kunit length of trail laid by the kth ant on the edge (i, j ) between time t and t - n . The quantity m Fvk ?1 ij k measures the additional trail traffic, whereFv ij ? Q / Lk if kth ant travels the edge (i, j ) in its tour in time [t , t - n], else 0 (6) kwhere Q is a constant and Lk is the tour length of the kth ant so that the shorter the tour is, themore will be the chemical reinforcement. The quantity of trail v ij at time t ? 0 is set to a smallconstant c . A data structure, say, cv list, where cv stands for “city-visited” is maintained. This list is adynamically growing vector that consists of all the cities already visited by an ant up to time t(maintaining the order in which
costefficiency of a hybrid approach—an attractive feature for institutions faced with shrinkingbudgets and classroom space—Brown13 posits that, in the future, institutions will design mostcourses by the 90–10 Rule Q (p. 22). In other words, a mix of face-to-face and online instruction(somewhere between 90% and 10% and 10% and 90%) will be superior to either 100% face-to-face or 100% online courses6. The findings of a study show that online learning can be aseffective as face-to-face learning in many respects in spite of the fact that students in onlineprograms may be less satisfied with their experience than students in more traditional learningenvironments14. In a study, participants who had more experience with the Internet indicatedsignificantly
Society for Engineering Education Annual Conference & Exposition Copyright © 2001, American Society for Engineering Education”At this point the students can guess that the some change to the uncertainty equation is neededto prevent the filter from “locking in” on a single answer that is really continuously changing, sothey are ready to be introduced to these discrete equations: σ x+ = φσ x− φ + q i i ∆t q = ∫e ne fτ fτ
state model, we define q1 = x1 , and q2 = x&1 , and obtain the following state equations q&1 0 1 q1 0 q& = −ω 2 + −2ζωn q2 K ωn2 F 2 nClearly all of the parameters in the state variable model can be obtained from the transferfunction for this system.Two Degree of Freedom System. The two degree of freedom system we utilize can be modeledas shown in Figure 5. For our equations there must be at least two springs present. The transferfunction
, the absolute value of the volumetric flow rate is applied to facilitateflow reversal computations. Conservation of mass applied at the common junction yields: Q1 - Q 2 - Q 3 = 0 (4)If the assumed flow directions are correct, equations 1-4 can be combined to form a singlenonlinear, algebraic equation that can be solved for the junction energy grade, EGLJ1, as: 1 1 C 1.85 1 D1 4.87 1.85
temperature, and that all of theevaporated water will be condensed and collected. This model will produce the equation: m% ? Q% / h fg where: Q% is the rate of solar energy incident on the “window” of the system. ( Q% = IA where I is the solar energy intensity (kW/m2) and A is the “window” area of your system (m2). hfg is heat of vaporization at water temperature. m% is the production rate of distilled water.To determine how much water your system can produce in 6 hours using this model, you willneed to research hourly values for solar energy intensity, I, (incident on a tilted surface?) inNew London in April and estimate the temperature of
Figure 2. Asynchronous templateFigure 3 below shows a classic SR latch, the most fundamental memory circuit studied inintroductory digital circuit courses. Figure 4 shows exactly the same circuit, but drawndifferently to emphasize the single feedback path, which holds the one state variable in thecircuit. The circuit remembers which of the two input variables, S or R, was most recently a 1,by recording on the output variable, Q, a 1 if it was S or a 0 if it was R. By realizing that this SRlatch, the most fundamental memory circuit in any static memory device, is actually anasynchronous finite state machine, one realizes the fundamental nature of this topic. S S
. q1 = C1v q1 = 1µF * 30V q1 = 30 µC Charge Pump AnalysisThen the total amount of charge that can be stored in C2 is calculated. Note that thevoltage on C2 is said to be 25 volts because of voltage drop across the diode. q2 = C 2 v q 2 = 10 µF * 25V q 2 = 250 µC Storage of C2 CapacitorIn order for the high side driver to maintain the desired voltage of 20 volts, the amount ofcharge being produced must be at least equal to the amount of charge being drawn, andideally the circuit should produce much more
analysis process. For any case, the first step in obtaining the wind loads is to determine the appropriatedynamic wind pressure. This pressure is obtained by treating the air as a perfect fluid and notingthat when wind strikes an object (a bluff body) in its path, the kinetic energy of the moving airparticles is converted to an effective dynamic wind pressure. This effective dynamic windpressure, q, at any height above ground is given by the following equation (Equation 6-13 inASCE 7):q z = 0.00256 K z K zt K d V 2 I (lb/ft2) (1)where,q = effective dynamic velocity pressure to be used in the appropriate equation to evaluate the effective static wind pressure for main wind-force
coefficients.Project ProblemsFirst five exercises are fairly straightforward. The purpose of exercise 1 will be apparent after theexercise 5.Exercise 1. Consider the linear differential equation y"+py '+qy = 0 with constant coefficients pand q. Let c1 , c 2 , c3 and c 4 be arbitrary real constants with c1c4 − c2 c3 ≠ 0. Show that u(x), theratio of independent solutions of the equation, takes one of the following three forms. c + c 2 tan(ax)Case I: If p2 - 4q < 0, then u(x) = 1 where a is a constant. c3 + c 4 tan(ax) c1 + c 2 e bxCase II: If p2 - 4q > 0, then u(x) = where b is a constant
; Exposition Copyright ©2005, American Society for Engineering Education” N p j (t + 1) = ∑ p i (t ) ⋅ q ij (t ), for j = 1,2, K , N i =1 N p (t + 1) = 1j4243 ∑ i =1 pi (t ) ⋅ 12 3 qij (t
theexpression for predicting the range of acceptable sample frequencies for such a bandpass signal is Q Q−1 2B ≤ Fs ≤ 2B (1) n n−1 Page 15.1328.1where Q = fU /B, and n is an integer such that 1 ≤ n ≤ ⌊Q⌋. In most real-world examples, thesignal’s frequency content is already specified, leaving n as the first choice the students must learn to Valid sampling frequencies for BP sampling
. ©American Society for Engineering Education, 2025 Thermo for KeepsAbstractThermodynamics is often the most hated course in the mechanical engineering curriculum.Why? Because when you add up all the possible combinations of applied equations, they becomeoverwhelming, with often subtle differences that are hard to remember. To counter this, four keyprinciples become a foundation. If these are well understood, simple math operations on thesemay create the rest. These principles are: 1. Q = mC∆T, 2. Understanding latent heat, 3.Understanding P∆V work, and 4. Law of the Turbine (an artifice for student discussionestablishing constant entropy across a turbine, in a piston, etc). Even the confusing differencebetween
ofthree students labeled P, Q, and R whom I believe to be representative, in a macro sense, of thedifferent ways in which students played the Novice level of the Spumone Drop challenge. Theletters P, Q, and R were chosen for convenience. Any relation that may exist between theseletters and the students’ actual names is coincidental.Student P. The way that that Student P played the novice and practice levels of the Dropchallenge is depicted in Figure 8. The horizontal lines represent timelines on two separate days.Vertical lines above the horizontal axis represent instances in which the student played the game.The practice level is essentially the same as the novice level, except there are no flowers to killthe spuCraft. The purpose of the
Page 25.1374.4randomly selected question set is generated for a weekly test. A weekly Q&A forum is setup sothat students can interact with each other any time and share common troubles they experience inthe course.Based on the feedback from the pilot period, the authors revised the course, as shown in Figure 2,to improve the learning process. The major revision includes excluding the use of publisher’shomework system and reorganizing learning activities to be more logically sequenced. Page 25.1374.5 Figure 2. Revised Learning Process for Spring 2012During the pilot phase, it was discovered that an independent
. L 02 Q3 C0 i in Q 1 i out a L 01 Ld id L 01 Q 1S Q3S Q 1L Q 3L RL i'S + Q2 iL VS
, which permitteddiscussion of methods to solve a single nonlinear algebraic equation. Vk~c Q(c_ci~)=_ (l+ Klc)2Next an unsteady CSTR at constant temperature was treated to introduce solving ordinary differential equationsas initial value problems.The model was then expanded to be steady but with heat effects included, and the Newton-Raphson method wasintroduced to solve sets of non-linear equations. Q % (yin -Y)= ~ v r(y,V Q Ctot M C& (T - Tin) = u v (-AH,..) r(y,T) kl y 0.05 10 r= kl = 6.70x 10 exp (–12556/T ), K, = 65.5 exp (961/T) T(l+K, y)2’In
applying the secure hash function SHA-1 or SHA-X. The data digest will beobtained. Subsequently, the data digest will be sent to a format function to create 4 polynomialsfor the signing and verifying process with collision detection. We then apply polynomialmultiplication algorithm in the digital signature scheme. The foundation of the latticed based polynomial public key cryptosystem is the ring R [2, 3],which consists of all truncated polynomials of degree N-1 having coefficients modulo q, i.e., f(X) = a0+a1X+a2X2+a3X3+...+aN-2XN-2+aN-1XN-1 (mod q). The lattice based polynomial digital signature scheme depends on the choice of a primenumber q and another number N. N represents the highest power of the polynomial f(αi