CONSENSUS STUDY REPORT K ey findings• T here is extens ive s exual haras s m ent• Gender haras s m ent is the m os t com m on form of s exual haras s m ent• S exual haras s m ent underm ines res earch integrity, reduces talent pool, and harm s targets and bys tanders• L egal com pliance is neces s ary but not s ufficient to reduce haras s m ent• Changing clim ate and culture can prevent and effectively addres s s exual haras s m ent Findings : Im pact on Targets and B ys tandersS exual haras s m ent underm ines wom en’s profes s ionaland educational attainm ent and m ental and phys icalhealth.S exual haras s m ent has advers e effects on not only thetargets of haras s m ent but als o bys
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Society for Engineering Education, 2019 T e c h n ic ia n -T e c h n o lo g y T e a m w o r k : M u ltifu n c tio n a l C o lla b o r a tio n o n I n d u s tr y P r o je c t sA b s tra c tT h e im p o r ta n c e o f m u ltif u n c tio n a l te a m w o r k h a s b e e n a d v o c a te d f o r s o m e tim e . T h is in c lu d e sh a v in g te c h n ic ia n s a n d e n g in e e r in g te c h n o lo g is ts le a rn to w o r k e ff e c tiv e ly to g e th e r . T h e g o a l o fth is p ilo t p r o je c t w a s to h a v e s tu d e n ts f r o m 2 -Y e a r a n d 4 - Y e a r p r o g r a m s le a r n to v a lu e th e irc o u n te r p a r ts b y w o rk in g to g e th e r o n a c o m b in e d
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Session 2 2 5 1 Engineering Education by An Application Oriented Design Ron K. Bhada, Abbas Ghassemi, J. Derald Morgan New Mexico State University Waste-management Education & Research ConsortiumIntroduction: Efficient and safe management of a sustainable environment is an increasingly critical national goal. It is a b r o a d i s s u e which c a n n o t b ea d d r e s s e d b y a n y o n e entity a n d r e q u i r e s a multi-disciplinary, multi-organizational a p p r o a c h . In 1990, the U . S . D e p a r t
(1c)The relationship (1a) corresponds to that of a resistor or equivalent; the relationship (1b)corresponds to that of an inductor or equivalent; and the relationship (1c) corresponds to that ofa capacitor or equivalent. These relationships are not required in the statement of the extendedTellegen’s theorem that we propose. However, they are required in the analysis. The analysismay be carried out either in the time-domain or in the Laplace transform domain. The Laplacetransform domain equations corresponding to Eqs. (1a), (1b) and (1c) are given below: Av(s) = k1 . Tv(s) (2a) Av(s) = (sk2) . Tv(s
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University PartnersBuilding a Sustainable Middle Class in AmericaW H A T I S B A S E 1 1 ? STEM workforce & entrepreneur accelerator Accelerating high potential lowresource students into the Victory CircleA N E M E R G I N G S T E MW O R K F O R C E — U N D E RR E P R E S E N T E D S E C T O R SBase 11 focuses on high potential, low resourcestudent sectors, Emphasizing: • Women, African Americans and Latinos who have the capabilities but are often not aware of or do not have access to the resources needed to take part The 1.0 Goal11,000 Students into the Victory Circle by 2020STEMEntrepreneurAcceleratorProducing 21st Century STEMEntrepreneursBase 11
application ofthe proposed algorithm.II. Formulation of AlgorithmConsider two polynomials in s, N(s) and D(s) over a field, given by: N(s) = ansn + an-1sn-1 + an-2sn-2 + . . . +a , 0 and (1) D(s) = bdsd + bd-1sd-1 + bd-2sd-2 + . . . +d 0Where d > or = n. D(s) = Q(s)N(s) + R(s). (2)It can be shown that the quotient polynomial Q(s) is of the form: Q(s) = bdsd-n/an + {c1sd-n-1 + c2sd-n-2 + ... + cd-n} (3)and the remainder polynomial R(s) is given by: R(s) = r1s n-1 + r2sn-2 + . . . + rn (4)A tableau can be constructed from
accomplishing that outcome. Finally, again as othershave done, the committees went the extra step of requiring course chairs to develop sub-outcomes (e.g., course outcomes) that give explicit guidance to faculty about specific results thatare required in individual courses if the broader program outcome(s) are to be achieved. It isthese course outcomes that have taken on a central role in the quality control process.Course Outcomes In identifying course outcomes, the intent of the curriculum committees was to create a setof clear metrics by which course successes could be judged. Thus, it was essential that courseoutcomes be stated in clear terms and in a way that lent them to objective measurement. To thatend, course chairs were charged with
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principal benefitsattributable to service-learning (S-L) dispersed through core required courses through surveys,interviews, and focus groups. As S-L continues to become a significant part of the community-engagement movement in higher education, and as more university professors are encouraged toincorporate S-L activities in their course requirements, it is essential that educators build anunderstanding of what students gain with S-L and that they give students a voice in their owneducational process and in the community. The service-learning (S-L) program SLICE (Service-Learning Integrated throughout a College of Engineering), based within the Francis College ofEngineering at the University of Massachusetts Lowell, began as a curricular reform
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allows the student to view both root locus andBode information. Unlike the GUI in this paper, the built in design tools are not based on theunified design procedures of the author’s previous work.9,10 Consequently, it does not providethe same seamless integration for the students as they transition from simple classroom exercisesto more complicated lab and design projects.Compensator DesignThe integrated design procedure using time or frequency domain plant data requires ageneralization of the angle criterion from root locus design. The standard closed-loop system isshown in Figure 1 where K is the control gain, Gc (s) is the compensator and G p ( s ) representsthe plant dynamics. R ( s
plant transfer function Gp(s) had to be easily isolated for open looptests, and the ability to close the loop had to also be included.Derivation of the CircuitThe basis for the simulator lies in the fact that differential equations can be solved/simulatedusing an analog computer. Using this fact, a circuit for simulating type 0 and type 1 systems canbe derived.For a type 0 system, Gp(s) = k/(s^2 + a s + b)Since Gp(s) represents the output Y(s) divided by the input R(s), Y(s)/R(s) = k/(s^2 + a s +b)or Y(s) (s^2 + a s +b) = k R(s)Taking the inverse Laplace transform, y’’(t) + a y’(t) + b y(t) = k r(t)or y’’(t) = k r(t) – a y’(t) – b y(t)This differential equation is simulated using the analog circuitry shown in
AC 2008-1616: INTEGRATING ENGINEERING ETHICS EDUCATION INTO AMULTI-DISCIPLINARY SEMINAR COURSE: MAKING THE “SOFT”OUTCOMES RELEVANTDavid Cottrell, University of North Carolina at Charlotte DR. DAVID S. COTTRELL is an Assistant Professor in the Department of Engineering Technology, University of North Carolina at Charlotte. He graduated from the United States Military Academy in 1978 and retired in 2000 after more than 22 years of service with the US Army Corps of Engineers. Studies at Texas A&M University resulted in an MS Degree in Civil Engineering in 1987 and a PhD in 1995. He is a registered Professional Engineer and has taught courses in statics, dynamics, mechanics of materials, graphic
s Armature Current Ia [ A ] 8.25 Stall Torque Tstall [ Nm ] 97.2 No-load angular velocity noload [ rad ] 150 s 2 Load Inertia J L [ kgm ] 5 Load Damping Coefficient DL [ Nms ] 30 rad
one period and areconsumed during a subsequent period. Special cases of this problem include mortgage financingas well as pension saving.Mathematical FormulationInvestment capital Q growing due to a saving rate S (t ) while simultaneously earning acontinuously compounded, after-tax, rate of investment return R satisfies the differentialequationQ’(t ) = RQ (t ) + S (t ), Q(0) = q 0 .The general solution of this equation for constant R is tQ(t ) = e [q0 + ∫ e − Rt S (t )dt ] Rt 0Inflation usually exists in real situations so it is desirable to think in terms of inflation adjustedcapital defined by q (t ) = Q(t )e − Itwhere I is the annual inflation rate. When I is zero, then q simply reduces to Q
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) A1Then the time domain equation for level in tank 1, in deviation form, is: l&1 (t ) = −a.l1 (t ) + b.l2 (t ) + c.v p (t ) Page 25.387.10 (18) where: ab 2g a= . A1 2( L1ss − L2 ss )0.5 ab 2g b= . Note: a = b A1 2( L1ss − L2 ss )0.5 Kp c= A1By taking the Laplace transform, equation (18) yields: s.l1 ( s
) responds well for a step change in the reference speed (ωr∗ ).Conclusion and Future WorkThis paper presents a design for the instructional advanced electric drives laboratory and itsimplementation . Off-the-shelf TI microcontroller DSK and industrial components were utilizedfor their cost-effectiveness and reliability as well as the hands-on experience they offer withinduction machine drive systems, up-to-date tools, and embedded programming. For future work,widely used serial communication interface (SCI), controller area network (CAN) bus and serialperipheral interface (SPI) can be considered for improved user interface and peripheralexpansion.References[1] S. A. Shirsavar, B. A. Potter, and I. M. L. Ridge. Three-phase machines and drives
AC 2009-2138: RECRUITMENT, RETENTION, AND SERVICE LEARNING INENGINEERINGJohn Duffy, University of Massachusetts, Lowell Professor, Mechanical EngineeringLinda Barrington, University of Massachusetts, Lowell Service-Learning Coordinator, College of EngineeringManuel Heredia, University of Massachusetts, Lowell Doctoral Research Assistant, Renewable Energy Engineering Page 14.1015.1© American Society for Engineering Education, 2009 Recruitment, Retention, and Service-Learning in EngineeringAbstractIn this study, an average of nearly 800 students per semester has participated in S-L projectsintegrated into courses throughout the four-year
]{ x} = {F (t )}Let x(0) and x (0) be the initial conditions representing the initial displacement and initialvelocity respectively. Applying the Laplace Transform, the above equation can bewritten as, s 2 [ M ] + s [C ] + [ K ] { x ( s )} = { F ( s )} + s [ M ] + [C ] { x(0)} + [ M ]{ x (0)} Page 12.1252.5For zero initial conditions,{ x(s)} = [ H (s)]{F (s)} ; where the Transfer Function, [ H (s)] = −1 s 2 [ M ] + s [C ] + [ K ]This matrix equation for the transfer function can be
ONR Command OverviewDr. Larry SchuetteDirector of ResearchMarch 2016 The Office of Naval ResearchThe S&T Provider for the Navy and Marine Corps • 4,000+ People • 23 Locations • $2.1B / year • >1,000 PartnersDiscover Develop Technological Deliver Advantage 2 Strategic Guidance is theFoundation for our Naval S&T National & Naval Strategy/Direction Warfare Enterprise’s S&T Objectives + Fleet Warfighting Capability Gaps
mechanical systems. Then, students will solve them by using a directmethod in the real domain and by applying the transform methods either in the frequency domain(Phasor Transform) or in the complex s-domain (Laplace Transform). Since the application oftransform techniques is much quicker and more efficient, especially when a real system carriesthe initial condition(s) or boundary conditions, we will focus on the Phasor Transform todetermine the steady-state response for an AC circuit and the Laplace Transform to derive thecomplete system solution, which includes transient and steady-state responses for both electricaland mechanical models. By offering a broad coverage of topics and case studies, this coursecould possibly be beneficial to the
provide more than 1,600 S-L experiences for engineering students with 25 community partners.Ms. Julianne Lee RhoadsProf. David O. Kazmer, University of Massachusetts, Lowell David Kazmer is a currently serving as the Associate Dean for the Francis College of Engineering at the University of Massachusetts, Lowell. Much of his teaching and research is motivated by industry experiences as an engineer and manager. He is the recipient of more than a dozen different recognition awards, an inventor with more than 20 patents, and the author of more than 200 publications, including two books. His teaching and research are in the areas of systems design, simulation, and optimization with a focus on machinery, sensors, and